6x^(2/3)-5x^(1/3)-6=0

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Solution for 6x^(2/3)-5x^(1/3)-6=0 equation: 


x in (-oo:+oo)

6*x^(2/3)-(5*x^(1/3))-6 = 0

6*x^(2/3)-5*x^(1/3)-6 = 0

t_1 = x^(1/3)

6*t_1^2-5*t_1^1-6 = 0

6*t_1^2-5*t_1-6 = 0

DELTA = (-5)^2-(-6*4*6)

DELTA = 169

DELTA > 0

t_1 = (169^(1/2)+5)/(2*6) or t_1 = (5-169^(1/2))/(2*6)

t_1 = 3/2 or t_1 = -2/3

t_1 = -2/3

x^(1/3)+2/3 = 0

1*x^(1/3) = -2/3 // : 1

x^(1/3) = -2/3

( -2/3 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 3/2

x^(1/3)-3/2 = 0

1*x^(1/3) = 3/2 // : 1

x^(1/3) = 3/2

x^(1/3) = 3/2 // ^ 3

x = 27/8

x = 27/8

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